Question
An object of mass 6.10 has an acceleration a = (1.13m/s^2)x + (-0.699m/s^)y. Three forces act on this object:F1, F2,and F3.Given that F1=(3.31N) and F2 = (-1.20 N)x + (1.83N)y, find F3.
Answers
TutorCat
Fnet=mass*acceleration
F=(6.10kg) sqrt[(1.13m/s^2)^2 + (-0.699m/s^2)^2]
Perform Pythagorean theorem (like I did with acceleration above) to find the net forces of F1 + F2.
Fnet = F1 + F2 + F3
Solve for F3.
F=(6.10kg) sqrt[(1.13m/s^2)^2 + (-0.699m/s^2)^2]
Perform Pythagorean theorem (like I did with acceleration above) to find the net forces of F1 + F2.
Fnet = F1 + F2 + F3
Solve for F3.