Asked by Anonymous
An object of mass 6.10 has an acceleration a = (1.13m/s^2)x + (-0.699m/s^)y. Three forces act on this object:F1, F2,and F3.Given that F1=(3.31N) and F2 = (-1.20 N)x + (1.83N)y, find F3.
Answers
Answered by
TutorCat
Fnet=mass*acceleration
F=(6.10kg) sqrt[(1.13m/s^2)^2 + (-0.699m/s^2)^2]
Perform Pythagorean theorem (like I did with acceleration above) to find the net forces of F1 + F2.
Fnet = F1 + F2 + F3
Solve for F3.
F=(6.10kg) sqrt[(1.13m/s^2)^2 + (-0.699m/s^2)^2]
Perform Pythagorean theorem (like I did with acceleration above) to find the net forces of F1 + F2.
Fnet = F1 + F2 + F3
Solve for F3.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.