Question

Darren and his two siblings' ages are three consecutive odd numbers. If the sum of their ages is 51, what are the three ages?


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Answer 1

Let's denote the ages of Darren and his two siblings as \( x \), \( x + 2 \), and \( x + 4 \), where \( x \) is the age of the youngest sibling, and since they are consecutive odd numbers, the subsequent ages follow this pattern.

We need to find \( x \) such that the sum of their ages equals 51:

\[
x + (x + 2) + (x + 4) = 51
\]

Combining the terms on the left side, we get:

\[
3x + 6 = 51
\]

Now, subtract 6 from both sides:

\[
3x = 51 - 6
\]
\[
3x = 45
\]

Next, divide both sides by 3:

\[
x = 15
\]

Now we can find the three ages:

- The youngest sibling's age, \( x \), is 15.
- The second sibling's age, \( x + 2 \), is \( 15 + 2 = 17 \).
- The oldest sibling's age, \( x + 4 \), is \( 15 + 4 = 19 \).

Thus, the three ages are:

15, 17, 19.