Asked by Anonymous
solve the inequality
|2y-5|>8
what will be the solution in interval notation
|2y-5|>8
what will be the solution in interval notation
Answers
Answered by
TutorCat
Something that helped me determine whether to set up a double inequality versus separate inequalities...
|expression|< k
less thAN (and)= double inequalities
-k<|expression|< k
|expression|> k
greatOR (or) = separate inequalities
|expression|< -k or |expression|> k
here's a link for further assistance:
http://www.algebralab.org/lessons/lesson.aspx?file=algebra_absolutevalueinequalities.xml
|expression|< k
less thAN (and)= double inequalities
-k<|expression|< k
|expression|> k
greatOR (or) = separate inequalities
|expression|< -k or |expression|> k
here's a link for further assistance:
http://www.algebralab.org/lessons/lesson.aspx?file=algebra_absolutevalueinequalities.xml
Answered by
Henry
[2x - 5] > 8.
Since the number inside the absolute
value brackets can be positive or negative,we'll have 3 solutions:
+-(2x - 5) > 8,
Solve for positive value:
+(2x - 5) > 8,
2x - 5 > 8,
2x > 8 + 5,
2x > 13,
x > 13/2.
Solve for negative value:
-(2x - 5) > 8,
-2x + 5 > 8,
-2x > 8 - 5,
-2x > 3,
x < -3/2.
Solution set: x < -3/2, and x > 13/2.
Since the number inside the absolute
value brackets can be positive or negative,we'll have 3 solutions:
+-(2x - 5) > 8,
Solve for positive value:
+(2x - 5) > 8,
2x - 5 > 8,
2x > 8 + 5,
2x > 13,
x > 13/2.
Solve for negative value:
-(2x - 5) > 8,
-2x + 5 > 8,
-2x > 8 - 5,
-2x > 3,
x < -3/2.
Solution set: x < -3/2, and x > 13/2.
Answered by
Henry
CORRECTION: We'll have 2 solutions, NOT
3.
3.
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