Question
solve the following word problem. the air temperature at 9 a.m is -5.8 degrees Celsius the air temperature at noon is -1.6 degrees Celsius.What is the change in the temperature during these three hours? write and solve an equation to show your answer then explain what your answer means. write it as a 7th grader
Answers
GPT-4o mini
To find the change in temperature from 9 a.m. to noon, we will write an equation based on the temperatures at those times.
1. **Identify the temperatures:**
- Temperature at 9 a.m.: \( T_1 = -5.8 \) degrees Celsius
- Temperature at noon: \( T_2 = -1.6 \) degrees Celsius
2. **Write the equation to find the change in temperature:**
The change in temperature (\( \Delta T \)) can be found by subtracting the initial temperature (\( T_1 \)) from the final temperature (\( T_2 \)):
\[
\Delta T = T_2 - T_1
\]
3. **Plug in the values:**
\[
\Delta T = -1.6 - (-5.8)
\]
4. **Simplify the equation:**
When you subtract a negative number, it's the same as adding:
\[
\Delta T = -1.6 + 5.8
\]
Now do the math:
\[
-1.6 + 5.8 = 4.2
\]
5. **Conclusion:**
So, the change in temperature during these three hours is \( 4.2 \) degrees Celsius.
### Explanation
This means that the temperature increased by \( 4.2 \) degrees Celsius from 9 a.m. to noon. It went from being quite cold at \( -5.8 \) degrees Celsius to a less cold temperature of \( -1.6 \) degrees Celsius. The positive change shows that the air got warmer over those three hours.
1. **Identify the temperatures:**
- Temperature at 9 a.m.: \( T_1 = -5.8 \) degrees Celsius
- Temperature at noon: \( T_2 = -1.6 \) degrees Celsius
2. **Write the equation to find the change in temperature:**
The change in temperature (\( \Delta T \)) can be found by subtracting the initial temperature (\( T_1 \)) from the final temperature (\( T_2 \)):
\[
\Delta T = T_2 - T_1
\]
3. **Plug in the values:**
\[
\Delta T = -1.6 - (-5.8)
\]
4. **Simplify the equation:**
When you subtract a negative number, it's the same as adding:
\[
\Delta T = -1.6 + 5.8
\]
Now do the math:
\[
-1.6 + 5.8 = 4.2
\]
5. **Conclusion:**
So, the change in temperature during these three hours is \( 4.2 \) degrees Celsius.
### Explanation
This means that the temperature increased by \( 4.2 \) degrees Celsius from 9 a.m. to noon. It went from being quite cold at \( -5.8 \) degrees Celsius to a less cold temperature of \( -1.6 \) degrees Celsius. The positive change shows that the air got warmer over those three hours.