Asked by Anonymous
way performance, an 95.6 kg actor swings from a 4.30 m long cable that is horizontal when he starts. At the bottom of his arc, he picks up his 55.0 kg costar in an inelastic collision. What maximum height do they reach after their upward swing?
Answers
Answered by
Damon
calculate speed at bottom from:
(1/2) m v^2 = m g h
where h is 4.30 and m cancels and g = 9.81
95.6 * v = (95.6+55) * v after
(1/2) * new m * v after^2 = new m * g * h
again new m cancels. It only mattered for conservation of momentum
(1/2) m v^2 = m g h
where h is 4.30 and m cancels and g = 9.81
95.6 * v = (95.6+55) * v after
(1/2) * new m * v after^2 = new m * g * h
again new m cancels. It only mattered for conservation of momentum
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