Question
Simplify the expression answer should have a positive exponent six to the third power and parentheses to the times to the second power times six to the -4th power over six to the second power
Answers
Answered by
GPT-4o mini
To simplify the expression \((6^3 \cdot 2^2 \cdot 6^{-4}) / 6^2\), we can follow these steps:
1. **Combine the powers of 6 in the numerator**:
\[
6^3 \cdot 6^{-4} = 6^{3 + (-4)} = 6^{-1}
\]
2. **Now, the expression looks like**:
\[
\frac{6^{-1} \cdot 2^2}{6^2}
\]
3. **Subtract the exponent in the denominator from the exponent in the numerator**:
\[
\frac{6^{-1}}{6^2} = 6^{-1 - 2} = 6^{-3}
\]
4. **Now include the \(2^2\) from the numerator**:
\[
2^2 \cdot 6^{-3} = 4 \cdot 6^{-3}
\]
5. **Since we want a positive exponent, we can rewrite \(6^{-3}\) as \(\frac{1}{6^3}\)**:
\[
= \frac{4}{6^3}
\]
6. **Now simplify \(\frac{4}{6^3}\)**:
\[
6^3 = 216, \quad \text{so}, \quad \frac{4}{216} = \frac{1}{54}
\]
Thus, the final simplified expression is:
\[
\frac{4}{216} \text{ or } \frac{1}{54}
\]
In summary,
\[
\frac{4}{6^3} \quad \text{or simply } \frac{1}{54}
\]
1. **Combine the powers of 6 in the numerator**:
\[
6^3 \cdot 6^{-4} = 6^{3 + (-4)} = 6^{-1}
\]
2. **Now, the expression looks like**:
\[
\frac{6^{-1} \cdot 2^2}{6^2}
\]
3. **Subtract the exponent in the denominator from the exponent in the numerator**:
\[
\frac{6^{-1}}{6^2} = 6^{-1 - 2} = 6^{-3}
\]
4. **Now include the \(2^2\) from the numerator**:
\[
2^2 \cdot 6^{-3} = 4 \cdot 6^{-3}
\]
5. **Since we want a positive exponent, we can rewrite \(6^{-3}\) as \(\frac{1}{6^3}\)**:
\[
= \frac{4}{6^3}
\]
6. **Now simplify \(\frac{4}{6^3}\)**:
\[
6^3 = 216, \quad \text{so}, \quad \frac{4}{216} = \frac{1}{54}
\]
Thus, the final simplified expression is:
\[
\frac{4}{216} \text{ or } \frac{1}{54}
\]
In summary,
\[
\frac{4}{6^3} \quad \text{or simply } \frac{1}{54}
\]
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