Asked by brian
                Calcu-
late the mass of pure acetic acid in 440 mL of
this solution at 20 C.
Answer in units of g.
            
            
        late the mass of pure acetic acid in 440 mL of
this solution at 20 C.
Answer in units of g.
Answers
                    Answered by
            DrBob222
            
    You must finish the problem.
    
                    Answered by
            brian
            
    i came up with the answer of 419 g
    
                    Answered by
            brian
            
    Th solution has a density of 1.049g/mL and only 40% of the solution is acetic acid
    
                    Answered by
            brian
            
    At normal temperature and pressure, air has
a density of 0.001184 g/mL. What is the mass
of air in a room that is 3.74 m by 3.45 m by
3.93 m?
Answer in units of kg.
                    Answered by
            DrBob222
            
    For the acetic acid problem I don't think the answer is 419 g. You can check it if you wish.
419 g/440 mL
440 mL with a density of 1.049 g/mL = mass of 440 x 1.049 = 461.6 grams and
(419/461.6)*100 = 90.7%; that isn't 40% so it must not be right.
    
419 g/440 mL
440 mL with a density of 1.049 g/mL = mass of 440 x 1.049 = 461.6 grams and
(419/461.6)*100 = 90.7%; that isn't 40% so it must not be right.
                    Answered by
            DrBob222
            
    For the air problem, I would convert each of the length, width, height in meters to cm, multiply to obtain volume in cc, then multiply by density to obtain grams air. Convert to kg. 
    
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