Suppose that the heights of adult men in the United States are normally distributed with a mean of inches and a standard deviation of inches. What proportion of the adult men in United States are more than feet tall? (Hint: feet inches.) Round your answer to at least four decimal places.

Answer 1

find the z-score:
z=(x-mu)/sigma
where mu= mean and sigma=standard deviation

after you find the z-score, you need to look at the z-score chart for the proportion
http://www.thebeststatistics.info/sta/table_zvals.html