Question

A city’s record high temperature is 106°F−17°F
and record low temperature is . How
much warmer is the city’s record high temperature than the record low temperature?
A. -89 Fahrenheit
B. 123 Fahrenheit
C. -123 Fahrenheit
D. 89 Fahrenheit

Answer 1

To find out how much warmer the city's record high temperature is than the record low temperature, we first need to clarify the values.

The record high temperature is given as:
\[
106°F - 17°F = 89°F
\]

The record low temperature is not provided, but let's denote it as \( L \).

We need to evaluate how much warmer the record high temperature (89°F) is than the record low temperature (L). This can be expressed as:
\[
89°F - L
\]

Since the question suggests comparing it to the options (A, B, C, D), and typically in such cases, a common record low might be assumed.

Assuming the record low temperature is typically significantly lower, let's consider the significant low temperatures that could be plausible in some cities.

1. Let's assume \( L = -34°F \) (just for calculation):
\[
89°F - (-34°F) = 89°F + 34°F = 123°F
\]

This indicates the city’s record high would be **123°F** warmer than this assumed record low.

Thus, if we assume that the record low temperature \( L = -34°F \):
- The correct answer would be **B. 123 Fahrenheit**, which matches with our calcualtion.

Unless you have the exact record low temperature or there’s a specific value you need to factor in, you can select from these options with consideration that the record high is 89°F.

So to answer your question as per the provided options and calculations:
\[
B. 123 Fahrenheit
\]