What is a rational number with a denominator of 7 that is between 7–√

and 8–√
. Write your answer as an improper fraction.(1 point)

1 answer

To find a rational number with a denominator of 7 that lies between \( 7 - \sqrt{7} \) and \( 8 - \sqrt{8} \), we first need to approximate the two values.

  1. Compute \( 7 - \sqrt{7} \):

    • The approximate value of \( \sqrt{7} \) is about 2.64575.
    • Thus, \( 7 - \sqrt{7} \approx 7 - 2.64575 \approx 4.35425 \).
  2. Compute \( 8 - \sqrt{8} \):

    • The approximate value of \( \sqrt{8} \) is about 2.82843.
    • Therefore, \( 8 - \sqrt{8} \approx 8 - 2.82843 \approx 5.17157 \).

Now we know that we need a rational number between approximately 4.35425 and 5.17157 with a denominator of 7.

  1. Convert possible rational numbers:
    • To find a suitable fraction, we check numbers of the form \( \frac{n}{7} \), where \( n \) is an integer.
    • We can multiply our bounds by 7 to convert these to integer values:
      • \( 4.35425 \times 7 \approx 30.5 \)
      • \( 5.17157 \times 7 \approx 36.2 \)

Thus, we need \( n \) to satisfy: \[ 30.5 < n < 36.2 \]

The integers \( n \) that fall within this range are \( 31, 32, 33, 34, 35, \) and \( 36 \).

  1. Choosing a rational number:

    • Let's pick \( n = 35 \): \[ \frac{35}{7} = 5 \]
  2. Check if it lies strictly between \( 7 - \sqrt{7} \) and \( 8 - \sqrt{8} \):

    • Since \( 5 \) is between \( 4.35425 \) and \( 5.17157 \), it satisfies our condition.

Thus, a rational number with a denominator of 7 that lies between \( 7 - \sqrt{7} \) and \( 8 - \sqrt{8} \) is:

\[ \frac{35}{7} \]