In the given chemical reaction:
\[ 2H_2 + O_2 \rightarrow 2H_2O \]
Before the reaction, you have 4 hydrogen atoms (since \(2H_2\) contains 2 molecules of hydrogen, each having 2 hydrogen atoms, resulting in \(2 \times 2 = 4\) H atoms).
After the reaction, you also have 4 hydrogen atoms present in the 2 molecules of water produced (since \(2H_2O\) contains 2 molecules of water, each having 2 hydrogen atoms, resulting in \(2 \times 2 = 4\) H atoms).
Therefore, the number of hydrogen atoms present after the reaction is:
4