Use multiplication to find the product that demonstrates the Closure Property of multiplication of polynomials.

(1/2^x2−3)(4y^3+5x^2)

(1 point)
Responses

2x2y3+52x4−12y3−15x2
2 x squared y cubed plus Start Fraction 5 over 2 End Fraction x superscript 4 baseline minus 12 y cubed minus 15 x squared

x2−−√y3+4x4−15x2
Start Root x squared End Root y cubed plus 4 x superscript 4 baseline minus 15 x squared

52x2y3+2x4−8y3+15x2
Start Fraction 5 over 2 End Fraction x squared y cubed plus 2 x superscript 4 baseline minus 8 y cubed plus 15 x squared

x2y3+5x4−8y3−15x2

1 answer

To demonstrate the Closure Property of multiplication of polynomials, we need to multiply the given polynomials:

\[ \left(\frac{1}{2}x^2 - 3\right)(4y^3 + 5x^2) \]

We'll distribute the first polynomial over the second:

  1. Multiply \(\frac{1}{2}x^2\) by \(4y^3\): \[ \frac{1}{2}x^2 \cdot 4y^3 = 2x^2y^3 \]

  2. Multiply \(\frac{1}{2}x^2\) by \(5x^2\): \[ \frac{1}{2}x^2 \cdot 5x^2 = \frac{5}{2}x^4 \]

  3. Multiply \(-3\) by \(4y^3\): \[ -3 \cdot 4y^3 = -12y^3 \]

  4. Multiply \(-3\) by \(5x^2\): \[ -3 \cdot 5x^2 = -15x^2 \]

Now, combine all these results: \[ 2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2 \]

Thus, the product of the two polynomials is: \[ 2x^2y^3 - 12y^3 + \frac{5}{2}x^4 - 15x^2 \]

From the options provided, we can select the one that matches our result: \[ \frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2 \]

This corresponds to: \[ \frac{5}{2} x^4 + 2 x^2 y^3 - 12 y^3 - 15 x^2 \]

So the correct response is: \(\frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2\)