To find the expanded form of 23.75, we break it down into its place values:
- The \(2\) in the tens place is \(2 \times 10\).
- The \(3\) in the ones place is \(3 \times 1\).
- The \(7\) in the tenths place is \(7 \times 0.1\) or \(7 \times \frac{1}{10}\).
- The \(5\) in the hundredths place is \(5 \times 0.01\) or \(5 \times \frac{1}{100}\).
However, in the given options, we must use integers. Looking closely, we notice that the expanded form should involve place values without decimals, so we'll express \(7\) and \(5\) in terms of a common unit (e.g., tenths and hundredths):
Now, let's analyze the provided options:
- (2×10) +(3x1) + (5x1) + (17×100)
- (2×10) +(3x1) + (7x1) + (5x1)
- (5×10) +(7x1) + (3x1) + (12x70)
- (2×10) +(3x1) +(7x16) + (5x100)
The first two terms, \(2 \times 10\) and \(3 \times 1\), are correct.
Let's evaluate the second option, \((2×10) +(3x1) + (7x1) + (5x1)\):
- \(2 \times 10 = 20\)
- \(3 \times 1 = 3\)
- \(7 \times 1 = 7\)
- \(5 \times 1 = 5\)
This option sums to \(20 + 3 + 7 + 5 = 35\), which is incorrect as \(23.75\) needs to shift.
Examining the first option, \((2×10) +(3x1) + (5x1) + (17×100)\):
- This scales to more than \(23\).
Finally, the rest of these options either do not conform or yield incorrect sums that don’t add properly to \(23.75\).
Given that every option employs a near 1s method, none provide a standard answer for \(23.75\) directly. The correct representation yet to highlight is the proposed addition shifted between the tens, ones, tenths, and hundredths representing decimals.
Thus, the answer concerning integers or decimal specifics centered around an if-in-between guide meant for expanded measures requires re-checking standard forms that align to nearly rounded figures, adhering to the domain if others should not mislead.
If an option must use some standards from \(23.75\), please direct clarity back to concise fractions or sub-units that maintain whether those remain inside \(23\). Adjustments carry overs well accordingly!