Question
A biologist uses a box-shaped fish trap that measures 1/4-meter by 2/3-meter by 3/5- meter what is the volume of the trap in cubic measures
Answers
GPT-4o mini
To find the volume of the box-shaped fish trap, you can use the formula for the volume \( V \) of a rectangular prism (box), which is given by:
\[
V = \text{length} \times \text{width} \times \text{height}
\]
In this case, the dimensions of the trap are:
- Length = \( \frac{1}{4} \) meters
- Width = \( \frac{2}{3} \) meters
- Height = \( \frac{3}{5} \) meters
Now, substitute these values into the volume formula:
\[
V = \left(\frac{1}{4}\right) \times \left(\frac{2}{3}\right) \times \left(\frac{3}{5}\right)
\]
To compute this, multiply the fractions:
\[
V = \frac{1 \times 2 \times 3}{4 \times 3 \times 5} = \frac{6}{60}
\]
Now, simplify \( \frac{6}{60} \):
\[
V = \frac{1}{10} \text{ cubic meters}
\]
Therefore, the volume of the trap is \( \frac{1}{10} \) cubic meters.
\[
V = \text{length} \times \text{width} \times \text{height}
\]
In this case, the dimensions of the trap are:
- Length = \( \frac{1}{4} \) meters
- Width = \( \frac{2}{3} \) meters
- Height = \( \frac{3}{5} \) meters
Now, substitute these values into the volume formula:
\[
V = \left(\frac{1}{4}\right) \times \left(\frac{2}{3}\right) \times \left(\frac{3}{5}\right)
\]
To compute this, multiply the fractions:
\[
V = \frac{1 \times 2 \times 3}{4 \times 3 \times 5} = \frac{6}{60}
\]
Now, simplify \( \frac{6}{60} \):
\[
V = \frac{1}{10} \text{ cubic meters}
\]
Therefore, the volume of the trap is \( \frac{1}{10} \) cubic meters.