A submarine was at a depth of 106.3

feet below sea level. After 5 hours, the submarine
was at 481.2
feet below sea level. How far did the submarine travel? Express your answer
as a decimal.
The submarine traveled ____ feet

1 answer

To find how far the submarine traveled, we need to calculate the difference in depth between the initial and final positions.

The initial depth of the submarine is: -106.3 feet (below sea level)

The final depth of the submarine is: -481.2 feet (below sea level)

We can calculate the distance traveled by finding the difference between the two depths:

\[ \text{Distance traveled} = \text{Final depth} - \text{Initial depth} \]

Substituting the values:

\[ \text{Distance traveled} = -481.2 - (-106.3) \] \[ = -481.2 + 106.3 \] \[ = -374.9 \text{ feet} \]

Since we are interested in the distance traveled (a positive value), we take the absolute value:

\[ \text{Distance traveled} = 374.9 \text{ feet} \]

Therefore, the submarine traveled 374.9 feet.