To solve the equation \( 3(x - 5) + 2x = 0 \), let's go step by step filling in the blanks.
- Distributing \( 3 \) in \( 3(x - 5) \): \[ 3x - 15 + 2x = 0 \]
So, we have:
- In the first response area: -15
- Combine like terms (the \( x \) terms): \[ 3x + 2x = 5x \]
So, we have:
- In the second response area: -15
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Now the equation looks like: \[ 5x - 15 = 0 \]
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To isolate \( x \), add \( 15 \) to both sides: \[ 5x = 15 \]
So, we have:
- In the third response area: 15
- Finally, divide by \( 5 \) to solve for \( x \): \[ x = 3 \]
So, we have:
- In the fourth response area: 3
Putting it all together, the filled responses are:
- For \( 3x + _ + 2x = 0 \): -15
- For \( 5x = _ \): 15
- For \( x = _ \): 3