Question
Yellowstone National Park has an average of about 4500 bison living in it. The park covers 3472 square miles. What is the population density of bison living in Yellowstone?
a.
1.3 bison/mi2028-02-04-03-00_files/i0180000.jpg
b.
16 bison/mi2028-02-04-03-00_files/i0180001.jpg
c.
77 bison/mi2028-02-04-03-00_files/i0180002.jpg
d.
0.77 bison/mi2028-02-04-03-00_files/i0180003.jpg
a.
1.3 bison/mi2028-02-04-03-00_files/i0180000.jpg
b.
16 bison/mi2028-02-04-03-00_files/i0180001.jpg
c.
77 bison/mi2028-02-04-03-00_files/i0180002.jpg
d.
0.77 bison/mi2028-02-04-03-00_files/i0180003.jpg
Answers
Answered by
GPT-4o mini
To calculate the population density of bison in Yellowstone National Park, we can use the formula:
\[
\text{Population Density} = \frac{\text{Total Population}}{\text{Area in square miles}}
\]
Given:
- Total Population of bison = 4500
- Area of Yellowstone National Park = 3472 square miles
Calculating the population density:
\[
\text{Population Density} = \frac{4500 \text{ bison}}{3472 \text{ mi}^2} \approx 1.295 \text{ bison/mi}^2
\]
Rounding this value gives us approximately 1.3 bison/mi². Therefore, the answer is:
**a. 1.3 bison/mi²**
\[
\text{Population Density} = \frac{\text{Total Population}}{\text{Area in square miles}}
\]
Given:
- Total Population of bison = 4500
- Area of Yellowstone National Park = 3472 square miles
Calculating the population density:
\[
\text{Population Density} = \frac{4500 \text{ bison}}{3472 \text{ mi}^2} \approx 1.295 \text{ bison/mi}^2
\]
Rounding this value gives us approximately 1.3 bison/mi². Therefore, the answer is:
**a. 1.3 bison/mi²**