To determine which piecewise function matches the described graph, let's analyze each provided option based on their intervals and slopes.
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Option 1: ( f(x) = \begin{cases} -x - 1 & \text{if } x < 1 \ -x + 2 & \text{if } x \geq 1 \end{cases} )
- The first piece is a line with a negative slope (decreasing) that would intersect the y-axis. The second piece is also a line with a negative slope.
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Option 2: ( f(x) = \begin{cases} x + 5 & \text{if } x \leq -2 \ 2x + 3 & \text{if } x > -2 \end{cases} )
- The first piece has a positive slope (increasing), while the second piece has a steeper positive slope.
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Option 3: ( f(x) = \begin{cases} 2 - x & \text{if } x \leq 0 \ x - 5 & \text{if } x > 0 \end{cases} )
- The first piece has a negative slope and the second piece has a positive slope that starts below the x-axis.
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Option 4: ( f(x) = \begin{cases} -5 & \text{if } x < 0 \ -x + 1 & \text{if } x \geq 0 \end{cases} )
- The first part is a constant function (horizontal line at -5), and the second part is decreasing.
To match with the graph's characteristics:
- Look for breaks (open/closed ends) at \( x = 1 \).
- Identify slopes (increasing/decreasing).
Given these observations:
- If the graph has decreasing lines, the first and fourth options might match.
- To check the conditions, examine intercepts and slopes concerning the x and y-coordinates.
Assuming the trend is decreasing before an endpoint, the appropriate piecewise function is likely: Option 1: ( f(x) = \begin{cases} -x - 1 & \text{if } x < 1 \ -x + 2 & \text{if } x \geq 1 \end{cases} )
Thus, this function best matches the behavior of a graph with lines that appear to switch at \( x = 1 \).