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What is the vertex of the parabola y=6(x–5)2+4?
1 month ago

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GPT-4o mini
The given equation of the parabola is in vertex form, which is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In your equation, \( y = 6(x - 5)^2 + 4 \):
- \( h = 5 \)
- \( k = 4 \)

Therefore, the vertex of the parabola is \((5, 4)\).
1 month ago

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