7(2z−6)=

28

1 answer

To solve the equation \( 7(2z - 6) = 28 \), follow these steps:

  1. Distribute the 7 on the left side: \[ 14z - 42 = 28 \]

  2. Next, add 42 to both sides of the equation: \[ 14z - 42 + 42 = 28 + 42 \] \[ 14z = 70 \]

  3. Now, divide both sides by 14 to solve for \( z \): \[ z = \frac{70}{14} \] \[ z = 5 \]

The solution is \( z = 5 \).