To solve the equation \( 2(y + 8) = 32 \), follow these steps:
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Distribute the 2 on the left side: \[ 2y + 16 = 32 \]
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Subtract 16 from both sides: \[ 2y = 32 - 16 \] \[ 2y = 16 \]
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Divide both sides by 2: \[ y = \frac{16}{2} \] \[ y = 8 \]
So, the solution is \( y = 8 \).