Asked by Dana
The equation of a circle C is
x^2 +y^2 +2x−4y−44=0 x^2+y^2+2x-4y-44 =0
What is its center (h,k) and its radius r
x^2 +y^2 +2x−4y−44=0 x^2+y^2+2x-4y-44 =0
What is its center (h,k) and its radius r
Answers
Answered by
Damon
x^2 + 2 x + y^2 -4 y = 44
x^2 + 2 x + 1 + y^2 - 4 y + 4 = 44+5 = 49
(x+1)^2 + (y-2)^2 = 7^2
center at (-1, 2) radius 7
x^2 + 2 x + 1 + y^2 - 4 y + 4 = 44+5 = 49
(x+1)^2 + (y-2)^2 = 7^2
center at (-1, 2) radius 7
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