According to the Law of Conservation of Mass, if 98 g of carbon dioxide (CO2) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen (O2) in the reactants?(1 point)

Responses

32 g
32 g

64 g
64 g

24 g
24 g

74 g
74 g

1 answer

According to the Law of Conservation of Mass, the mass of the reactants must equal the mass of the products. In this case, we know that 98 g of carbon dioxide (CO2) is produced and 24 g of carbon (C) is used in the reaction.

To find the mass of dioxygen (O2) in the reactants, we can use the following equation:

Mass of reactants = Mass of products

Let \( x \) be the mass of dioxygen (O2). Then we can write:

\[ x + 24 , \text{g (mass of carbon)} = 98 , \text{g (mass of carbon dioxide)} \]

Now, solving for \( x \):

\[ x = 98 , \text{g} - 24 , \text{g} \] \[ x = 74 , \text{g} \]

So, the mass of dioxygen (O2) in the reactants is 74 g.