How many atoms of carbon (C) are present in the reactants of the following chemical equation?

2C6H10 + 17O2 → 12CO2 + 10H2O

(1 point)
Responses

7 atoms
7 atoms

1 atom
1 atom

16 atoms
16 atoms

12 atoms
12 atoms

1 answer

To determine the number of carbon (C) atoms in the reactants of the given chemical equation:

\[ 2C_6H_{10} + 17O_2 \]

We can analyze the reactants:

  • The compound \(C_6H_{10}\) contains 6 carbon atoms. Since there are 2 molecules of \(C_6H_{10}\), we can calculate the total number of carbon atoms as follows:

\[ \text{Number of carbon atoms from } C_6H_{10} = 2 \times 6 = 12 \text{ carbon atoms} \]

The other reactant, \(O_2\), does not contain any carbon atoms.

Therefore, the total number of carbon atoms in the reactants is 12.

The correct answer is: 12 atoms