A submarine was at a depth of 106.3

Question

feet below sea level. After 5 hours, the submarine was at 481.2
feet below sea level. How far did the submarine travel? Express your answer as a decimal.(1 point)
The submarine traveled
feet.

Answer 1

To find out how far the submarine traveled, we need to calculate the difference in depth from its initial position to its final position.

1. Initial depth: 106.3 feet below sea level
2. Final depth: 481.2 feet below sea level

To find the distance traveled, we subtract the initial depth from the final depth:

\[ \text{Distance traveled} = \text{Final depth} - \text{Initial depth} \]

In this case:

\[ \text{Distance traveled} = 481.2 - 106.3 \]

Now, calculating that:

\[ \text{Distance traveled} = 481.2 - 106.3 = 374.9 \]

Thus, the submarine traveled 374.9 feet.