Jaydin draws a triangle on the coordinate grid. Its vertices are at (−4,3)

, (−1,−5)
, and (−2,6)
. He translates this triangle 5 units up and 2 units to the right. What are the coordinates of the lowest vertex on the translated triangle?

(1,0)
left parenthesis 1 comma 0 right parenthesis

(−2,8)
left parenthesis negative 2 comma 8 right parenthesis

(4,−3)
left parenthesis 4 comma negative 3 right parenthesis

(0,1)

1 answer

To find the coordinates of the lowest vertex on the translated triangle, we first need to determine the lowest vertex of the original triangle with vertices at (-4, 3), (-1, -5), and (-2, 6).

From the given vertices:

  • (-4, 3)
  • (-1, -5)
  • (-2, 6)

The lowest vertex among these is (-1, -5).

Next, we need to translate this vertex 5 units up and 2 units to the right.

  1. Translating 5 units up means we add 5 to the y-coordinate: \[ -5 + 5 = 0 \]

  2. Translating 2 units to the right means we add 2 to the x-coordinate: \[ -1 + 2 = 1 \]

Now, the new coordinates of the lowest vertex after the translation will be: \[ (1, 0) \]

Thus, the coordinates of the lowest vertex on the translated triangle are (1, 0). The correct answer is: (1, 0).