To determine the total bond energy in the products of the reaction \( \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \), we need to consider the bonds in the products, which are 2 H-Cl bonds.
According to the table, the bond energy for each H-Cl bond is 427 kJ/mol. Since there are 2 H-Cl bonds in the products of the reaction (2 HCl), we need to multiply the bond energy of one H-Cl bond by 2:
\[ \text{Total bond energy in products} = 2 \times 427 \text{ kJ/mol} = 854 \text{ kJ/mol} \]
Therefore, the total bond energy in the products of the reaction is 854 kJ/mol.