Question

4+3c/7=c/7+8

Answer 1

To solve the equation \( 4 + \frac{3c}{7} = \frac{c}{7} + 8 \), we will first eliminate the fractions by multiplying the entire equation by 7:

\[
7 \left( 4 + \frac{3c}{7} \right) = 7 \left( \frac{c}{7} + 8 \right)
\]

This simplifies to:

\[
28 + 3c = c + 56
\]

Next, we'll isolate the variable \( c \). First, subtract \( c \) from both sides:

\[
28 + 3c - c = 56
\]

This simplifies to:

\[
28 + 2c = 56
\]

Now, subtract 28 from both sides:

\[
2c = 56 - 28
\]

This simplifies to:

\[
2c = 28
\]

Finally, divide both sides by 2:

\[
c = \frac{28}{2} = 14
\]

So, the solution is:

\[
c = 14
\]