Point A is on line EB between points E and B, and ray AF forms adjacent angles EAF with a measure of 4x and FAB with a measure of 2x.

Solve for x.
x = 6°
x = 15°
x = 30°
x = 90°

1 answer

To find \( x \), we start by noting that angles \( EAF \) and \( FAB \) are adjacent angles that share the line EB. Therefore, we can set up the equation:

\[ \text{measure of } \angle EAF + \text{measure of } \angle FAB = 180^\circ \]

Given:

  • \( \text{measure of } \angle EAF = 4x \)
  • \( \text{measure of } \angle FAB = 2x \)

Substituting these values into the equation gives us:

\[ 4x + 2x = 180^\circ \]

Combining like terms:

\[ 6x = 180^\circ \]

Now, divide both sides by 6:

\[ x = \frac{180^\circ}{6} = 30^\circ \]

Thus, the solution is:

\[ x = 30^\circ \]

So, the correct answer is 30°.