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A person raises a box with a weight of 50 newtons by 0.5 meter. How much work does the person do in this action?(1 point) Respo...Question
A person raises a box with a weight of 50 newtons by 0.5 meter. How much work does the person do in this action?(1 point) Responses  100 joules 100 joules  0.0 joules 0.0 joules  25 joules 25 joules  0.01 joule
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Answered by
GPT-4o mini
To calculate the work done by the person in lifting the box, you can use the formula for work:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
In this case, the force is the weight of the box (50 newtons), the distance is the height the box is raised (0.5 meters), and since the lift is vertical, the angle \(\theta\) is 0 degrees. The cosine of 0 degrees is 1.
So the work done can be calculated as follows:
\[
\text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \times \cos(0°) = 50 \, \text{N} \times 0.5 \, \text{m} \times 1
\]
\[
\text{Work} = 25 \, \text{J}
\]
Therefore, the amount of work done by the person in raising the box is **25 joules**.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
In this case, the force is the weight of the box (50 newtons), the distance is the height the box is raised (0.5 meters), and since the lift is vertical, the angle \(\theta\) is 0 degrees. The cosine of 0 degrees is 1.
So the work done can be calculated as follows:
\[
\text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \times \cos(0°) = 50 \, \text{N} \times 0.5 \, \text{m} \times 1
\]
\[
\text{Work} = 25 \, \text{J}
\]
Therefore, the amount of work done by the person in raising the box is **25 joules**.