Question
What is the atomic mass of a triatomic elementary gas with a vapour density of 48
Answers
GPT-4o mini
To find the atomic mass of a triatomic elementary gas with a vapor density of 48, we can use the relationship between vapor density and molar mass. The vapor density (VD) is defined as half the molar mass (M) of the gas at the same temperature and pressure.
The formula is:
\[
\text{Vapor Density (VD)} = \frac{M}{2}
\]
From the given vapor density of 48, we can set up the equation:
\[
48 = \frac{M}{2}
\]
To solve for \(M\):
\[
M = 48 \times 2 = 96 \text{ g/mol}
\]
Thus, the molar mass of the triatomic elementary gas is 96 g/mol. Given that it is a triatomic elementary gas, this mass would typically represent the combined mass of three atoms in one molecule of the gas.
If we were looking for the atomic mass of a single atom in this triatomic molecule, we would need to divide the total molar mass by 3 (as there are three atoms in the molecule) assuming that the atoms are of equal mass:
\[
\text{Atomic mass per atom} = \frac{96 \text{ g/mol}}{3} = 32 \text{ g/mol}
\]
So, the atomic mass of each atom in the triatomic elementary gas would be approximately 32 g/mol. Keep in mind that this assumes an equal distribution of mass among the three atoms, which is a simplification.
The formula is:
\[
\text{Vapor Density (VD)} = \frac{M}{2}
\]
From the given vapor density of 48, we can set up the equation:
\[
48 = \frac{M}{2}
\]
To solve for \(M\):
\[
M = 48 \times 2 = 96 \text{ g/mol}
\]
Thus, the molar mass of the triatomic elementary gas is 96 g/mol. Given that it is a triatomic elementary gas, this mass would typically represent the combined mass of three atoms in one molecule of the gas.
If we were looking for the atomic mass of a single atom in this triatomic molecule, we would need to divide the total molar mass by 3 (as there are three atoms in the molecule) assuming that the atoms are of equal mass:
\[
\text{Atomic mass per atom} = \frac{96 \text{ g/mol}}{3} = 32 \text{ g/mol}
\]
So, the atomic mass of each atom in the triatomic elementary gas would be approximately 32 g/mol. Keep in mind that this assumes an equal distribution of mass among the three atoms, which is a simplification.