Question

Charlotte has a bag of candy. In her bag, she has 6 cherry candies, 3 grape candies, and 3 lime candies.


If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry? Round to the nearest hundredth.

Answer 1

To calculate the probability of Charlotte pulling out a cherry candy, we first need to find the total number of candies in the bag.

Charlotte has:
- 6 cherry candies
- 3 grape candies
- 3 lime candies

Now we calculate the total number of candies:

\[
\text{Total candies} = 6 + 3 + 3 = 12
\]

Next, we find the probability of pulling out a cherry candy. The probability \( P \) of an event is given by the formula:

\[
P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}}
\]

In this case, the number of favorable outcomes for pulling out a cherry candy is 6 (the number of cherry candies), and the total number of outcomes is 12 (the total number of candies).

Thus, the probability of pulling out a cherry candy is:

\[
P(\text{cherry}) = \frac{6}{12} = \frac{1}{2}
\]

To convert this to a decimal:

\[
\frac{1}{2} = 0.5
\]

Now, rounding to the nearest hundredth, we get:

\[
P(\text{cherry}) \approx 0.50
\]

Therefore, the probability that Charlotte will pull out a cherry candy is \(\boxed{0.50}\).