To solve the equation \( 5x^{4/3} = 80 \), follow these steps:
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First, divide both sides by 5: \[ x^{4/3} = \frac{80}{5} \] \[ x^{4/3} = 16 \]
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Next, to eliminate the fractional exponent, raise both sides to the reciprocal of \( \frac{4}{3} \), which is \( \frac{3}{4} \): \[ x = 16^{3/4} \]
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Rewrite \( 16 \) as \( 2^4 \): \[ x = (2^4)^{3/4} \]
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Simplify the right side: \[ x = 2^{4 \cdot \frac{3}{4}} = 2^3 = 8 \]
Thus, the solution to the equation \( 5x^{4/3} = 80 \) is: \[ \boxed{8} \]