To add the fractions \(-1 \frac{1}{3}\) and \(-4 \frac{2}{3}\), we can first convert them to improper fractions.
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Convert \(-1 \frac{1}{3}\) to an improper fraction: \[ -1 \frac{1}{3} = -\left(1 \times 3 + 1\right)/3 = -\frac{4}{3} \]
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Convert \(-4 \frac{2}{3}\) to an improper fraction: \[ -4 \frac{2}{3} = -\left(4 \times 3 + 2\right)/3 = -\frac{14}{3} \]
Now we can add these two fractions together: \[ -\frac{4}{3} + (-\frac{14}{3}) = -\frac{4 + 14}{3} = -\frac{18}{3} = -6 \]
So, the result of \(-1 \frac{1}{3} + (-4 \frac{2}{3})\) is \(-6\).