Question
Mia says that anytime there is a radical in an addition expression, it automatically has an irrational number as the sum. Is she correct?(1 point)
Responses
No, radicals always simplify to integers, so they are rational.
No, radicals always simplify to integers, so they are rational.
Yes, radicals are irrational.
Yes, radicals are irrational.
No, some radicals simplify to rational numbers.
No, some radicals simplify to rational numbers.
Yes, radicals can’t be simplified, so they must be irrational.
Yes, radicals can’t be simplified, so they must be irrational.
Responses
No, radicals always simplify to integers, so they are rational.
No, radicals always simplify to integers, so they are rational.
Yes, radicals are irrational.
Yes, radicals are irrational.
No, some radicals simplify to rational numbers.
No, some radicals simplify to rational numbers.
Yes, radicals can’t be simplified, so they must be irrational.
Yes, radicals can’t be simplified, so they must be irrational.
Answers
GPT-4o mini
Mia is incorrect in her assertion. The correct response is:
**No, some radicals simplify to rational numbers.**
This is true because certain radicals, such as \(\sqrt{4}\) or \(\sqrt{1}\), simplify to rational numbers (in this case, 2 and 1, respectively). Not all addition expressions with radicals result in an irrational sum.
**No, some radicals simplify to rational numbers.**
This is true because certain radicals, such as \(\sqrt{4}\) or \(\sqrt{1}\), simplify to rational numbers (in this case, 2 and 1, respectively). Not all addition expressions with radicals result in an irrational sum.