To determine the approximate value of \(\sqrt{28}\), we can find the perfect squares around it.
- \(4^2 = 16\)
- \(5^2 = 25\)
- \(6^2 = 36\)
Since \(25 < 28 < 36\), this means that:
\[ 5 < \sqrt{28} < 6 \]
Now, we can refine our estimate. We can calculate \(\sqrt{28}\) more specifically:
\[ \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \]
To further approximate \(\sqrt{7}\), we note:
\[ 2.6^2 = 6.76 \quad \text{and} \quad 2.7^2 = 7.29 \]
So \(\sqrt{7}\) is approximately between \(2.6\) and \(2.7\). Therefore:
\[ 2\sqrt{7} \approx 2 \times 2.6 = 5.2 \quad \text{to} \quad 2 \times 2.7 = 5.4 \]
Thus, \(\sqrt{28}\) is approximately between \(5.2\) and \(5.4\), which places it closer to \(5\).
Given this information, the correct statement is:
It is between 5 and 6, probably closer to 5.