Note the correct spelling of celsius.
q = mass x specific heat x (Tfinal-Tintial)
how much energy is required to heat 1.00L of water from 20degrees celcius to 90degress celcius
3 answers
(Heat in Joules) = (mass in grams) x (specific heat) x (temperature change)
1 L = 1000 grams & specific heat of water = 4.184 J/gram Degree Celsius
Temp Change = 90 - 20 = 70 Deg C
Heat = 1000 g x 4.184 J/g Deg C X 20 Deg C =
83680 J
With 2 significant figures your answer would be 84 kJ
With 3 significant figures your answer would be 83.7 kJ
1 L = 1000 grams & specific heat of water = 4.184 J/gram Degree Celsius
Temp Change = 90 - 20 = 70 Deg C
Heat = 1000 g x 4.184 J/g Deg C X 20 Deg C =
83680 J
With 2 significant figures your answer would be 84 kJ
With 3 significant figures your answer would be 83.7 kJ
How many formul units of LiOH are in 134.5gof LiOH