Polygon ABCD with vertices at A(−4, 6), B(−2, 2), C(4, −2), D(4, 4) is dilated using a scale factor of one fourth to create polygon A′B′C′D′. Determine the vertices of polygon A′B′C′D′.

A′(−0.8, 1.2), B′(−0.4, 0.4), C′(0.8, −0.4), D′(0.8, 0.8)
A′(−1, 1.5), B′(−0.5, 0.5), C′(1, −0.5), D′(1, 1)
A′(−2, 3), B′(−1, 1), C′(2, −1), D′(2, 2)
A′(−3, 4.5), B′(−1.5, 1.5), C′(3, −1.5), D′(3, 3)

1 answer

To find the vertices of polygon A′B′C′D′ after dilating polygon ABCD with a scale factor of \(\frac{1}{4}\), we will apply the scale factor to each vertex.

The formula to apply a dilation with scale factor \( k \) from the origin \( (0, 0) \) is:

\[ (x', y') = (k \cdot x, k \cdot y) \]

Given \( k = \frac{1}{4} \), we will apply this to each vertex of polygon ABCD.

  1. Vertex A(−4, 6): \[ A' = \left(\frac{1}{4} \cdot -4, \frac{1}{4} \cdot 6\right) = (-1, 1.5) \]

  2. Vertex B(−2, 2): \[ B' = \left(\frac{1}{4} \cdot -2, \frac{1}{4} \cdot 2\right) = (-0.5, 0.5) \]

  3. Vertex C(4, −2): \[ C' = \left(\frac{1}{4} \cdot 4, \frac{1}{4} \cdot -2\right) = (1, -0.5) \]

  4. Vertex D(4, 4): \[ D' = \left(\frac{1}{4} \cdot 4, \frac{1}{4} \cdot 4\right) = (1, 1) \]

Now we can summarize the coordinates of the dilated polygon A′B′C′D′:

  • A′(−1, 1.5)
  • B′(−0.5, 0.5)
  • C′(1, −0.5)
  • D′(1, 1)

Looking at the provided options, the correct vertices of polygon A′B′C′D′ are:

A′(−1, 1.5), B′(−0.5, 0.5), C′(1, −0.5), D′(1, 1).