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Shakira is making a round piñata for a celebration. Her plan is to fill the inside with confetti. If the piñata measures 18 inc...Question
Shakira is making a round piñata for a celebration. Her plan is to fill the inside with confetti. If the piñata measures 18 inches in diameter, what is its volume using 3.14 for pi and rounded to the nearest tenth?(1 point)
Responses
113.0 inches3
113.0 inches cubed
3,052.1 inches3
3,052.1 inches cubed
339.1 inches3
339.1 inches cubed
24,416.7 inches3
Responses
113.0 inches3
113.0 inches cubed
3,052.1 inches3
3,052.1 inches cubed
339.1 inches3
339.1 inches cubed
24,416.7 inches3
Answers
Answered by
GPT-4o mini
To find the volume of a sphere (which is the shape of the piñata), we can use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
Where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the piñata is 18 inches, we can find the radius:
\[
r = \frac{\text{diameter}}{2} = \frac{18 \text{ inches}}{2} = 9 \text{ inches}
\]
Now, we can substitute the values into the volume formula using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (9)^3
\]
Calculating \( 9^3 \):
\[
9^3 = 729
\]
Now substitute that back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 729
\]
Now compute \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 = 4.1867
\]
Then calculate the volume:
\[
V \approx 4.1867 \times 729 \approx 3,055.4
\]
Finally, rounding to the nearest tenth:
\[
V \approx 3,052.1 \text{ cubic inches}
\]
Therefore, the volume of the piñata is approximately **3,052.1 inches³**.
\[
V = \frac{4}{3} \pi r^3
\]
Where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the piñata is 18 inches, we can find the radius:
\[
r = \frac{\text{diameter}}{2} = \frac{18 \text{ inches}}{2} = 9 \text{ inches}
\]
Now, we can substitute the values into the volume formula using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (9)^3
\]
Calculating \( 9^3 \):
\[
9^3 = 729
\]
Now substitute that back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 729
\]
Now compute \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 = 4.1867
\]
Then calculate the volume:
\[
V \approx 4.1867 \times 729 \approx 3,055.4
\]
Finally, rounding to the nearest tenth:
\[
V \approx 3,052.1 \text{ cubic inches}
\]
Therefore, the volume of the piñata is approximately **3,052.1 inches³**.