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Polygon JKLM is drawn with vertices J(−4, −4), K(−4, −6), L(−1, −6), M (−1, −4). Determine the image coordinates of L′ if the p...Question
Polygon JKLM is drawn with vertices J(−4, −4), K(−4, −6), L(−1, −6), M(−1, −4). Determine the image coordinates of K′ if the preimage is reflected across y = −7.
K′(−4, −4)
K′(−4, −5)
K′(−4, 6)
K′(−4, −8)
K′(−4, −4)
K′(−4, −5)
K′(−4, 6)
K′(−4, −8)
Answers
Answered by
GPT-4o mini
To reflect the point \( K(-4, -6) \) across the line \( y = -7 \), we can follow these steps:
1. **Determine the distance from the point to the line**: The y-coordinate of point K is -6. The line \( y = -7 \) is below point K, so we find the distance between -6 and -7.
\[
\text{Distance} = -6 - (-7) = -6 + 7 = 1
\]
2. **Find the reflected point**: Since the distance is 1 unit above the line, the reflected point will be 1 unit below the line \( y = -7 \).
\[
y\text{-coordinate of } K' = -7 - 1 = -8
\]
3. **Keep the x-coordinate the same**: The x-coordinate of K is -4, therefore the coordinates of the reflected point \( K' \) are:
\[
K'(-4, -8)
\]
The image coordinates of \( K' \) are \( (-4, -8) \). Therefore, the correct choice among the options provided is:
**K′(−4, −8)**.
1. **Determine the distance from the point to the line**: The y-coordinate of point K is -6. The line \( y = -7 \) is below point K, so we find the distance between -6 and -7.
\[
\text{Distance} = -6 - (-7) = -6 + 7 = 1
\]
2. **Find the reflected point**: Since the distance is 1 unit above the line, the reflected point will be 1 unit below the line \( y = -7 \).
\[
y\text{-coordinate of } K' = -7 - 1 = -8
\]
3. **Keep the x-coordinate the same**: The x-coordinate of K is -4, therefore the coordinates of the reflected point \( K' \) are:
\[
K'(-4, -8)
\]
The image coordinates of \( K' \) are \( (-4, -8) \). Therefore, the correct choice among the options provided is:
**K′(−4, −8)**.