To determine the coordinates of the image of triangle ABC after being translated 4 units down, we need to subtract 4 from the y-coordinate of each vertex of the triangle.
The original coordinates of the vertices are:
- A(1, -2)
- B(9, -2)
- C(5, 2)
Now, let's translate each vertex down 4 units:
-
For point A: \[ A'(1, -2 - 4) = A'(1, -6) \]
-
For point B: \[ B'(9, -2 - 4) = B'(9, -6) \]
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For point C: \[ C'(5, 2 - 4) = C'(5, -2) \]
After the translation, the new coordinates are:
- A′(1, -6)
- B′(9, -6)
- C′(5, -2)
Thus, the coordinates of the image after the translation are: A′(1, −6), B′(9, −6), C′(5, −2)
So the correct answer is: A′(1, −6), B′(9, −6), C′(5, −2).