Question
Which molecule contains the largest number of oxygen atoms? (2 points)
Group of answer choices
BeSO3
Ba(OH)2
NaOH
Al2(SO4)3
Group of answer choices
BeSO3
Ba(OH)2
NaOH
Al2(SO4)3
Answers
GPT-4o mini
To determine which molecule contains the largest number of oxygen atoms, let's count the oxygen atoms in each of the given compounds:
1. **BeSO3**: This molecule contains 3 oxygen atoms (1 from SO3).
2. **Ba(OH)2**: This molecule contains 2 hydroxide groups, each containing 1 oxygen. Therefore, it has a total of 2 oxygen atoms.
3. **NaOH**: This molecule contains 1 oxygen atom (from the hydroxide ion, OH).
4. **Al2(SO4)3**: This molecule contains 3 sulfate ions (SO4), and each sulfate has 4 oxygen atoms. Thus, it contains a total of \(3 \times 4 = 12\) oxygen atoms.
Now, we can compare:
- BeSO3: 3 oxygen atoms
- Ba(OH)2: 2 oxygen atoms
- NaOH: 1 oxygen atom
- Al2(SO4)3: 12 oxygen atoms
Hence, **Al2(SO4)3** contains the largest number of oxygen atoms, which is **12**.
1. **BeSO3**: This molecule contains 3 oxygen atoms (1 from SO3).
2. **Ba(OH)2**: This molecule contains 2 hydroxide groups, each containing 1 oxygen. Therefore, it has a total of 2 oxygen atoms.
3. **NaOH**: This molecule contains 1 oxygen atom (from the hydroxide ion, OH).
4. **Al2(SO4)3**: This molecule contains 3 sulfate ions (SO4), and each sulfate has 4 oxygen atoms. Thus, it contains a total of \(3 \times 4 = 12\) oxygen atoms.
Now, we can compare:
- BeSO3: 3 oxygen atoms
- Ba(OH)2: 2 oxygen atoms
- NaOH: 1 oxygen atom
- Al2(SO4)3: 12 oxygen atoms
Hence, **Al2(SO4)3** contains the largest number of oxygen atoms, which is **12**.