When rolling a 6-sided die twice, determine P(sum of 6).

Question

twelve thirty sixths
seven thirty sixths
five thirty sixths
two sixths

Answer 1

To find the probability of rolling a sum of 6 when rolling a 6-sided die twice, we first need to identify all the possible outcomes that add up to 6:

Here are the combinations of the two rolls (first die, second die) that sum to 6:

1. (1, 5)
2. (2, 4)
3. (3, 3)
4. (4, 2)
5. (5, 1)

So there are 5 combinations that yield a sum of 6.

Next, we need to determine the total number of possible outcomes when rolling two 6-sided dice. Since each die has 6 faces, the total number of outcomes is: \[ 6 \times 6 = 36 \]

Now, we can calculate the probability of rolling a sum of 6: \[ P(\text{sum of 6}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{5}{36} \]

Thus, the probability of rolling a sum of 6 when rolling a 6-sided die twice is \( \frac{5}{36} \).

From the options provided:

• twelve thirty-sixths
• seven thirty-sixths
• five thirty-sixths (this is our correct answer)
• two sixths

The correct answer is five thirty-sixths.