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The equation of the line of best fit is y = -9.21x + 168.7.

Based on the line of best fit, approximately how far is a 5-pound pumpkin predicted to travel when launched by the catapult?

1 answer

To find out how far a 5-pound pumpkin is predicted to travel using the line of best fit given by the equation \( y = -9.21x + 168.7 \), you need to substitute \( x = 5 \) into the equation.

  1. Substitute \( x \) with 5: \[ y = -9.21(5) + 168.7 \]

  2. Calculate \( -9.21 \times 5 \): \[ -9.21 \times 5 = -46.05 \]

  3. Now add this value to 168.7: \[ y = -46.05 + 168.7 = 122.65 \]

So, the predicted distance that a 5-pound pumpkin would travel when launched by the catapult is approximately 122.65 units (the units would depend on the context, such as feet, meters, etc.).