Question

What is the value of this expression when a = 4, b = -5, and c = -7?
A+2bc over 3a

Answer 1

To evaluate the expression \(\frac{A + 2bc}{3a}\) when \(a = 4\), \(b = -5\), and \(c = -7\), we first need to calculate the term \(2bc\).

1. Calculate \(bc\):
\[
bc = (-5)(-7) = 35
\]

2. Now multiply by 2:
\[
2bc = 2 \cdot 35 = 70
\]

3. Next, we need to consider the value of \(A\). However, since \(A\) is not provided in your question, we will assume \(A = 0\) for simplicity in demonstrating how to solve the expression. If \(A\) has a specific value you intend, please provide that.

If we assume \(A = 0\), then:
\[
A + 2bc = 0 + 70 = 70
\]

4. Now calculate \(3a\):
\[
3a = 3 \cdot 4 = 12
\]

5. Now substitute back into the expression:
\[
\frac{A + 2bc}{3a} = \frac{70}{12}
\]

6. Simplify \(\frac{70}{12}\):
\[
\frac{70}{12} = \frac{35}{6}
\]

So, assuming \(A = 0\), the value of the expression is \(\frac{35}{6}\).

If you had a different value for \(A\), please provide it, and I can adjust the calculation accordingly.