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What is the value of this expression when a = 4, b = -5, and c = -7?

A+2bc over 3a

1 answer

To evaluate the expression \(\frac{A + 2bc}{3a}\) when \(a = 4\), \(b = -5\), and \(c = -7\), we first need to calculate the term \(2bc\).

  1. Calculate \(bc\): \[ bc = (-5)(-7) = 35 \]

  2. Now multiply by 2: \[ 2bc = 2 \cdot 35 = 70 \]

  3. Next, we need to consider the value of \(A\). However, since \(A\) is not provided in your question, we will assume \(A = 0\) for simplicity in demonstrating how to solve the expression. If \(A\) has a specific value you intend, please provide that.

    If we assume \(A = 0\), then: \[ A + 2bc = 0 + 70 = 70 \]

  4. Now calculate \(3a\): \[ 3a = 3 \cdot 4 = 12 \]

  5. Now substitute back into the expression: \[ \frac{A + 2bc}{3a} = \frac{70}{12} \]

  6. Simplify \(\frac{70}{12}\): \[ \frac{70}{12} = \frac{35}{6} \]

So, assuming \(A = 0\), the value of the expression is \(\frac{35}{6}\).

If you had a different value for \(A\), please provide it, and I can adjust the calculation accordingly.