how would you solve 5!+4!

solve 5! solve 4! then add the solutions
add 5 add 4 then find the factorial of the sum
solve 5! solve 4! then subtract the solutions
cancel the 4x3x2x1 then solve for what is left

1 answer

To solve \(5! + 4!\), we start by calculating each factorial:

  1. Calculate \(5!\): \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]

  2. Calculate \(4!\): \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \]

  3. Add the two results: \[ 5! + 4! = 120 + 24 = 144 \]

So, the final answer is: \[ \boxed{144} \]

The other methods proposed (adding 5 and 4 and then finding the factorial of the sum, subtracting the solutions, and canceling terms) would not correctly yield the solution for \(5! + 4!\). The straightforward method of calculating each factorial and then adding them is the correct approach.