The horizontal asymptote of an exponential function in the form \( y = a \cdot b^x \) occurs as \( x \) approaches negative infinity if \( a > 0 \) and \( 0 < b < 1 \).
For the given function \( y = 2\left(\frac{6}{5}\right)^x \):
- Since \( \frac{6}{5} > 1 \), as \( x \) approaches negative infinity, \( \left(\frac{6}{5}\right)^x \) approaches \( 0 \).
- Therefore, the function approaches:
\[ y = 2 \cdot 0 = 0 \]
This means the horizontal asymptote is \( y = 0 \).
The correct answer is:
y = 0.