Question
How much wrapping paper is needed to cover a cube-shaped gift with a side length of 8 cm?
Answers
GPT-4o mini
To find the amount of wrapping paper needed to cover a cube-shaped gift, we need to calculate the surface area of the cube. The formula for the surface area \(A\) of a cube with side length \(s\) is given by:
\[
A = 6s^2
\]
In this case, the side length \(s\) is 8 cm.
Now, we can substitute \(s\) into the formula:
\[
A = 6(8 \, \text{cm})^2
\]
Calculating \(8^2\):
\[
8^2 = 64 \, \text{cm}^2
\]
Now substituting back into the surface area formula:
\[
A = 6 \times 64 \, \text{cm}^2 = 384 \, \text{cm}^2
\]
Therefore, the amount of wrapping paper needed to cover the cube-shaped gift is
\[
\boxed{384 \, \text{cm}^2}
\]
\[
A = 6s^2
\]
In this case, the side length \(s\) is 8 cm.
Now, we can substitute \(s\) into the formula:
\[
A = 6(8 \, \text{cm})^2
\]
Calculating \(8^2\):
\[
8^2 = 64 \, \text{cm}^2
\]
Now substituting back into the surface area formula:
\[
A = 6 \times 64 \, \text{cm}^2 = 384 \, \text{cm}^2
\]
Therefore, the amount of wrapping paper needed to cover the cube-shaped gift is
\[
\boxed{384 \, \text{cm}^2}
\]