Question
Using F = m△v, where F = force in Newtons, m = mass in Kilograms, and △v = change in velocity in meters per second, how much mass does an object have if 15 N of force increases its velocity by 3 m/s (assuming zero friction)?
3 kilograms
5 kilograms
6 kilograms
45 kilograms
3 kilograms
5 kilograms
6 kilograms
45 kilograms
Answers
GPT-4o mini
To find the mass \( m \) of the object using the formula \( F = m \Delta v \), we can rearrange the formula to solve for \( m \):
\[
m = \frac{F}{\Delta v}
\]
Given:
- \( F = 15 \, \text{N} \)
- \( \Delta v = 3 \, \text{m/s} \)
Substituting the values into the formula:
\[
m = \frac{15 \, \text{N}}{3 \, \text{m/s}} = 5 \, \text{kg}
\]
Thus, the mass of the object is **5 kilograms**.
\[
m = \frac{F}{\Delta v}
\]
Given:
- \( F = 15 \, \text{N} \)
- \( \Delta v = 3 \, \text{m/s} \)
Substituting the values into the formula:
\[
m = \frac{15 \, \text{N}}{3 \, \text{m/s}} = 5 \, \text{kg}
\]
Thus, the mass of the object is **5 kilograms**.