volume of cylinder πr^2h
you know volume and height, let's sub
1 = πr^2(6)
r^2 = 1/(6π)
r = √1/6π)
you do the button-pushing.
a) cylinder has volume 1m3 and height of 0.6m.
How do I fifure the missing dimension. Could someone please provide me with a formula to figure this out. Also can someone please explain to me step by step how to do this. Cause it takes me a long time to understand things clearly.
you know volume and height, let's sub
1 = πr^2(6)
r^2 = 1/(6π)
r = √1/6π)
you do the button-pushing.
Volume = πr²h
where:
- Volume is the given volume of the cylinder (1m³ in this case),
- π is the mathematical constant approximately equal to 3.14159,
- r is the radius of the base of the cylinder, which is the missing dimension we want to calculate, and
- h is the height of the cylinder (0.6m in this case).
To find the missing dimension (radius, r), we need to rearrange the formula:
r² = Volume / (πh)
Now, let's plug in the known values. The volume is given as 1m³, and the height is 0.6m. Using these values, we can solve step by step:
1. Substitute the known values into the formula:
r² = 1 / (π * 0.6)
2. Simplify the right side of the equation:
r² = 1 / (0.6π)
3. Calculate the value of 0.6π using a calculator (or use an approximation such as 3.14159):
r² ≈ 1 / 1.88496
4. Divide 1 by the value obtained in step 3:
r² ≈ 0.53109
5. Take the square root of both sides to find the value of r:
r ≈ √0.53109
6. Use a calculator to find the approximate value of √0.53109:
r ≈ 0.729
Therefore, the missing dimension, the radius (r), is approximately 0.729 meters.